From 147a19e84a743f1379f05bf2f444143b4afd7bd6 Mon Sep 17 00:00:00 2001 From: Yuchen Pei Date: Fri, 18 Jun 2021 12:58:44 +1000 Subject: Updated. --- ...ry-words-containing-repetitions-odd-periods.org | 67 ++++++++++++++++++++++ 1 file changed, 67 insertions(+) create mode 100644 posts/2015-05-30-infinite-binary-words-containing-repetitions-odd-periods.org (limited to 'posts/2015-05-30-infinite-binary-words-containing-repetitions-odd-periods.org') diff --git a/posts/2015-05-30-infinite-binary-words-containing-repetitions-odd-periods.org b/posts/2015-05-30-infinite-binary-words-containing-repetitions-odd-periods.org new file mode 100644 index 0000000..b632c03 --- /dev/null +++ b/posts/2015-05-30-infinite-binary-words-containing-repetitions-odd-periods.org @@ -0,0 +1,67 @@ +#+title: AMS review of 'Infinite binary words containing repetitions of +#+title: odd period' by Badkobeh and Crochemore + +#+date: <2015-05-30> + +This paper is about the existence of pattern-avoiding infinite binary +words, where the patterns are squares, cubes and \(3^+\)-powers.    +There are mainly two kinds of results, positive (existence of an +infinite binary word avoiding a certain pattern) and negative +(non-existence of such a word). Each positive result is proved by the +construction of a word with finitely many squares and cubes which are +listed explicitly. First a synchronising (also known as comma-free) +uniform morphism \(g\: \Sigma_3^* \to \Sigma_2^*\) + +is constructed. Then an argument is given to show that the length of +squares in the code \(g(w)\) for a squarefree \(w\) is bounded, hence +all the squares can be obtained by examining all \(g(s)\) for \(s\) of +bounded lengths. The argument resembles that of the proof of, e.g., +Theorem 1, Lemma 2, Theorem 3 and Lemma 4 in [N. Rampersad, J. O. +Shallit and M. Wang, Theoret. Comput. Sci. *339* (2005), no. 1, 19--34; +[[http://www.ams.org/mathscinet/search/publdoc.html?r=1&pg1=MR&s1=2142071&loc=fromrevtext][MR2142071]]]. +The negative results are proved by traversing all possible finite words +satisfying the conditions. + +   Let \(L(n_2, n_3, S)\) be the maximum length of a word with \(n_2\) +distinct squares, \(n_3\) distinct cubes and that the periods of the +squares can take values only in \(S\) , where \(n_2, n_3 \in \Bbb N \cup +\{\infty, \omega\}\) and \(S \subset \Bbb N_+\) .    \(n_k = 0\) +corresponds to \(k\)-free, \(n_k = \infty\) means no restriction on the +number of distinct \(k\)-powers, and \(n_k = \omega\) means +\(k^+\)-free. + +   Below is the summary of the positive and negative results: + +1) (Negative) \(L(\infty, \omega, 2 \Bbb N) < \infty\) : \(\nexists\) an + infinite \(3^+\) -free binary word avoiding all squares of odd + periods. (Proposition 1) + +2) (Negative) \(L(\infty, 0, 2 \Bbb N + 1) \le 23\) : \(\nexists\) an + infinite 3-free binary word, avoiding squares of even periods. The + longest one has length \(\le 23\) (Proposition 2). + +3) (Positive) \(L(\infty, \omega, 2 \Bbb N + + + 1) - = \infty\) :: \(\exists\) an infinite \(3^+\) -free binary word + avoiding squares of even periods (Theorem 1). + +4) (Positive) \(L(\infty, \omega, \{1, 3\}) = \infty\) : \(\exists\) an + infinite \(3^+\) -free binary word containing only squares of period + 1 or 3 (Theorem 2). + +5) (Negative) \(L(6, 1, 2 \Bbb N + 1) = 57\) : \(\nexists\) an infinite + binary word avoiding squares of even period containing \(< 7\) + squares and \(< 2\) cubes. The longest one containing 6 squares and 1 + cube has length 57 (Proposition 6). + +6) (Positive) \(L(7, 1, 2 \Bbb N + 1) = \infty\) : \(\exists\) an + infinite \(3^+\) -free binary word avoiding squares of even period + with 1 cube and 7 squares (Theorem 3). + +7) (Positive) \(L(4, 2, 2 \Bbb N + 1) = \infty\) : \(\exists\) an + infinite \(3^+\) -free binary words avoiding squares of even period + and containing 2 cubes and 4 squares (Theorem 4). + +Copyright notice: This review is published at +http://www.ams.org/mathscinet-getitem?mr=3313467, its copyright owned by +the AMS. -- cgit v1.2.3