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authorDominic Steinitz <dominic@steinitz.org>2015-05-16 13:53:14 +0100
committerDominic Steinitz <dominic@steinitz.org>2015-12-21 08:07:11 +0000
commit3f50b955324bd4b42f88a421f0203bc46a3ccf64 (patch)
tree822a3c2e5779e87712552959b6b4987f1286e0ba /html-test/ref/Math.html
parente01e4790402204af02ab0127ef5b633fb7748cd4 (diff)
Fix the documentation for haddock itself.
Change notation and add support for inline math. Allow newlines in display math. Add a command line option for the mathjax url (you might want to use a locally installed version). Rebase tests because of extra url and version change. Respond to (some of the) comments. Fix warnings in InterfaceFile.hs
Diffstat (limited to 'html-test/ref/Math.html')
-rw-r--r--html-test/ref/Math.html22
1 files changed, 21 insertions, 1 deletions
diff --git a/html-test/ref/Math.html b/html-test/ref/Math.html
index 3335f7b1..5b76fd13 100644
--- a/html-test/ref/Math.html
+++ b/html-test/ref/Math.html
@@ -7,6 +7,8 @@
><link href="ocean.css" rel="stylesheet" type="text/css" title="Ocean"
/><script src="haddock-util.js" type="text/javascript"
></script
+ ><script src="https://cdn.mathjax.org/mathjax/latest/MathJax.js?config=TeX-AMS-MML_HTMLorMML" type="text/javascript"
+ ></script
><script type="text/javascript"
>//<![CDATA[
window.onload = function () {pageLoad();setSynopsis("mini_Math.html");};
@@ -41,6 +43,22 @@ window.onload = function () {pageLoad();setSynopsis("mini_Math.html");};
><p class="caption"
>Math</p
></div
+ ><div id="description"
+ ><p class="caption"
+ >Description</p
+ ><div class="doc"
+ ><p
+ >Math (display) for <code
+ >normalDensity</code
+ ></p
+ ><p
+ >\[
+ \int_{-\infty}^{\infty} e^{-x^2/2} = \sqrt{2\pi}
+ \]</p
+ ><p
+ >\(\int_{-\infty}^{\infty} e^{-x^2/2} = \sqrt{2\pi}\)</p
+ ></div
+ ></div
><div id="synopsis"
><p id="control.syn" class="caption expander" onclick="toggleSection('syn')"
>Synopsis</p
@@ -67,7 +85,9 @@ window.onload = function () {pageLoad();setSynopsis("mini_Math.html");};
><p
>Math (inline) for <code
>normalDensity</code
- > $$\int_{-\infnty}^{\infty} e^{-x^2/2} = sqrt{2\pi}$$</p
+ >
+ \(\int_{-\infty}^{\infty} e^{-x^2/2} = \sqrt{2\pi}\)
+ \[\int_{-\infty}^{\infty} e^{-x^2/2} = \sqrt{2\pi}\]</p
></div
></div
></div