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authorYuchen Pei <me@ypei.me>2019-02-20 13:58:42 +0100
committerYuchen Pei <me@ypei.me>2019-02-20 13:58:42 +0100
commit73441883d96685ecc9d837a8834da73c92ab276a (patch)
treebf78bd1a5169ab89369424178d5ac153030304f9 /posts/2019-02-14-raise-your-elbo.md
parentc24a34b2d2bb7632c56ac5018d076aa4b1784337 (diff)
fixed issue #1.
Diffstat (limited to 'posts/2019-02-14-raise-your-elbo.md')
-rw-r--r--posts/2019-02-14-raise-your-elbo.md2
1 files changed, 1 insertions, 1 deletions
diff --git a/posts/2019-02-14-raise-your-elbo.md b/posts/2019-02-14-raise-your-elbo.md
index 34e7386..5d4c2dd 100644
--- a/posts/2019-02-14-raise-your-elbo.md
+++ b/posts/2019-02-14-raise-your-elbo.md
@@ -172,7 +172,7 @@ $$\begin{aligned}
&= \text{argmax}_\theta \sum_i \mathbb E_{p(z_{i} | x_{i}; \theta_t)} \log p(x_{i}, z_{i}; \theta) \qquad (2.3)
\end{aligned}$$
-So $\sum_i L(p(x_{i}), z_{i}; \theta)$ is non-decreasing at both the
+So $\sum_i L(p(x_{i}, z_{i}; \theta), q(z_i)$ is non-decreasing at both the
E-step and the M-step.
We can see from this derivation that EM is half-Bayesian. The E-step is